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Chest reward ( random item )

N

Nuelman

Member
Joined
Nov 9, 2017
Messages
98
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V 10.99 tfs 1.x
Hello,
Already I have this script:
Lua: 
local rewards = {
  { item = 9019, count = 1 },
  { item = 5809, count = 1 },
  { item = 8982, count = 1 }
}   

local YOUR_STORAGE_NUMBER = 5000

function onUse(player, item, fromPosition, itemEx, toPosition, isHotkey)
    if player:getStorageValue(YOUR_STORAGE_NUMBER) ~= 1 then
        local random = math.random(1, #rewards)
        player:addItem(rewards[random].item, rewards[random].count)
        player:sendTextMessage(36, 'You have found '.. ItemType(rewards[random].item):getName() ..'.')
        player:setStorageValue(YOUR_STORAGE_NUMBER, 1)
    else
         player:sendTextMessage(MESSAGE_EVENT_ADVANCE, "You already opened this chest.")
    end
    return true
end

I would like to change the possibility of obtaining for each object. (chance)

I would also like to add, that you can use the reward chest again after 10 hours.

Is it possible?

+rep
 
Solution
Xikini
Nuelman said:
But is diferent versión tfs.
THIS work for 10.99m

And On the question, to use the chest again after a few hours, is there a solution? Thank you
Post automatically merged:

Up
Click to expand...
This should work.

-- minor edit to code to fix a small issue on line 27
Lua: 
local rewards = {
    { item = 9019, count = 1, chance = 50 },
    { item = 5809, count = 1, chance = 50 },
    { item = 8982, count = 1, chance = 50 }
}

local YOUR_STORAGE_NUMBER = 5000
local delay_timer = 36000 -- in seconds 60*60*10 = 10 hours ()

function onUse(player, item, fromPosition, itemEx, toPosition, isHotkey)

    local cur_time, cur_storage = os.time(), player:getStorageValue(YOUR_STORAGE_NUMBER)
 
    if cur_storage > cur_time then...
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Sneaky Diller said:
@Xikini can you make give reward in bag?
Click to expand...
otland.net

[TFS 1.X] Give player items by table

inspired by @Xikini, his code for 0.x linked here If someone wants to convert the scant amount of actual functions for TFS 1.0+, please do so. function Player.giveItems(self, t) local cap = (ItemType(1988):getWeight() / 100) * (math.floor(#t / 20) + 1) for i = 1, #t do local v...
otland.net otland.net
 
Upvote 0 Downvote
Is there a way to make sure you get only 1 reward out of the suggested reward items?
100% chance, no cd, only 1 out of x items.
Thanks.
 
Upvote 0 Downvote
DarkLua said:
Is there a way to make sure you get only 1 reward out of the suggested reward items?
100% chance, no cd, only 1 out of x items.
Thanks.
Click to expand...
Just make sure that the total % adds up to a 100%
Example:
Lua: 
local rewards = {
    { item = 28552, count = 500, chance = 16 },
    { item = 28553, count = 500, chance = 16 },
    { item = 28554, count = 500, chance = 16 },
    { item = 28555, count = 500, chance = 16 },
    { item = 28556, count = 500, chance = 16 },
    { item = 28557, count = 500, chance = 16 }
}
 
Upvote 0 Downvote

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