<? Php error

[president vankk]

Error:

A PHP Error was encountered
Severity: Notice
Message: Undefined variable: data
Filename: shop/shop.php
Line Number: 55

Line 55:

foreach($SQL->query('SELECT * FROM players WHERE account_id="'.$data['id'].'"') as $chars)

A PHP Error was encountered
Severity: Notice
Message: Undefined variable: loggedAccId
Filename: sources/history.php
Line Number: 23

Line 23:

$historyQueryPacc = "SELECT * FROM z_shop_admin_todo WHERE from_account='".$loggedAccId."' OR to_account='".$loggedAccId."';";

What problem? :s

 

[tatu hunter]

Its not a problem, its only a Notice (possible bugs in your code), this cause by your var $data and $loggedAccId which dont have any value.

to fix this go to your /index.php find

error_reporting(E_ALL);

change to:

error_reporting(E_ALL ^ E_NOTICE);

 

[PineIt]

Its not a problem, its only a Notice (possible bugs in your code), this cause by your var $data and $loggedAccId which dont have any value.

to fix this go to your /index.php find

error_reporting(E_ALL);

change to:

error_reporting(E_ALL ^ E_NOTICE);

That does most certainly not solve it. It simply hides the error which is something you should NEVER EVER do. It is better to solve the error rather than to suppress it.

Please show us a bit more of your code in case you do want our support!

 

[president vankk]

Its not a problem, its only a Notice (possible bugs in your code), this cause by your var $data and $loggedAccId which dont have any value.

to fix this go to your /index.php find

error_reporting(E_ALL);

change to:

error_reporting(E_ALL ^ E_NOTICE);

and problem with creating character??

how to fix?

 

[tatu hunter]

we need the error output to solve your problem...

what is the link to your site?

 

[Archez]

You are taking those $vars from nowhere.