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Solved How to construct party?

whitevo

whitevo

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I'm trying to create a party with Lua lines, but I can't seem to construct the Party userdata.
Can it be done in Lua? If not, what I need to do so I could make Party like that: Party(userdata)
 
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Found this, maybe something works

Code: 
party:addInvite(player)
party:addMember(player)
party:disband()
party:getInviteeCount()
party:getInvitees()
party:getLeader()
party:getMemberCount()
party:getMembers()
party:isSharedExperienceActive()
party:isSharedExperienceEnabled()
party:removeInvite(player)
party:removeMember(player)
party:setLeader(player)
party:setSharedExperience(active)
party:shareExperience(experience)
 
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Cornex said:
Found this, maybe something works

Code: 
party:addInvite(player)
party:addMember(player)
party:disband()
party:getInviteeCount()
party:getInvitees()
party:getLeader()
party:getMemberCount()
party:getMembers()
party:isSharedExperienceActive()
party:isSharedExperienceEnabled()
party:removeInvite(player)
party:removeMember(player)
party:setLeader(player)
party:setSharedExperience(active)
party:shareExperience(experience)
Click to expand...
Theese are function if you alrady have the party.
Codex NG said:
Party is already a metatable, you might write over it if you re-define it with userdata.
Code: 
function Party:onJoin(player)
    return true
end
https://github.com/otland/forgotten...7f82d10769f205c/data/events/scripts/party.lua
Click to expand...
Yet its not listed in the functions.

EDIT: But I found something interesting thanks to your hint.
<event class="Party" method="onJoin" enabled="0" />
This needs to be turned OFF then this method works.

EDIT2: However this wont still create new instance of party to use and manipulate.
Printer said:
https://github.com/otland/forgottenserver/commit/3c9a6aec934209876d296fdee96690686132b35f
Click to expand...
Nice, Why this change has not taken place in master branch yet?
 
Last edited:
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@Printer
How do you create party with your code?
Party(playerUserdata) does not work for me

(I compiled your changes to source in linux)

When I loop trough Party metatable, I also see no option to create it.
 
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Code: 
local party = Party(player)
if party then
print("Party has been created.")
else
print("Fail to create party.")
end
 
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Printer said:
Code: 
local party = Party(player)
if party then
print("Party has been created.")
else
print("Fail to create party.")
end
Click to expand...
yep, doesnt work.
Sais Party is table value

Err: attempt to call global Party (a table value)

EDIT:
NVM me.. I was testing it on wrong server not on the one I did source edits. Yep works perfectly.
 
Last edited:
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Is it possible to activate Shared Exp by LUA script when there is no option available for client? If so, does anyone have it?
 
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A few months ago I did something like this:
Code: 
diff --git a/src/luascript.cpp b/src/luascript.cpp
index 24cde70..d6d042a 100644
--- a/src/luascript.cpp
+++ b/src/luascript.cpp
@@ -2187,6 +2187,7 @@ void LuaScriptInterface::registerFunctions()
     registerMethod("Player", "getSlotItem", LuaScriptInterface::luaPlayerGetSlotItem);
+    registerMethod("Player", "createParty", LuaScriptInterface::luaPlayerCreateParty);
     registerMethod("Player", "getParty", LuaScriptInterface::luaPlayerGetParty);
     registerMethod("Player", "addOutfit", LuaScriptInterface::luaPlayerAddOutfit);
@@ -7474,6 +7475,7 @@ int LuaScriptInterface::luaPlayerCreate(lua_State* L)
     return 1;
}
+
int LuaScriptInterface::luaPlayerIsPlayer(lua_State* L)
{
     // player:isPlayer()
@@ -8721,6 +8723,32 @@ int LuaScriptInterface::luaPlayerGetSlotItem(lua_State* L)
     return 1;
}
+int LuaScriptInterface::luaPlayerCreateParty(lua_State* L)
+{
+    // player:createParty(targetPlayer[, joinTargetPlayer = false])
+    Player* player = getUserdata<Player>(L, 1);
+    Player* targetPlayer = getUserdata<Player>(L, 2);
+    if (!player || !targetPlayer) {
+        lua_pushnil(L);
+        return 1;
+    }
+
+    Party* partyPlayer = player->getParty();
+    Party* partyInvitedPlayer = targetPlayer->getParty();
+
+    if (!partyPlayer && !partyInvitedPlayer) {
+        partyPlayer = new Party(player);
+        partyPlayer->invitePlayer(*targetPlayer);
+        bool joinTargetPlayer = getBoolean(L, 3, false);
+        if (joinTargetPlayer) {
+            partyPlayer->joinParty(*targetPlayer);
+        }
+        pushUserdata<Party>(L, partyPlayer);
+        setMetatable(L, -1, "Party");
+    }
+    return 1;
+}
+
int LuaScriptInterface::luaPlayerGetParty(lua_State* L)
{
     // player:getParty()
diff --git a/src/luascript.h b/src/luascript.h
index 3f50e63..543de7f 100644
--- a/src/luascript.h
+++ b/src/luascript.h
@@ -928,6 +928,7 @@ class LuaScriptInterface
         static int luaPlayerGetSlotItem(lua_State* L);
+        static int luaPlayerCreateParty(lua_State* L);
         static int luaPlayerGetParty(lua_State* L);
         static int luaPlayerAddOutfit(lua_State* L);



You can use like this:
Code: 
local other_player = Player(players[2])
player:createParty(other_player, true)
local party = player:getParty()
party:setSharedExperience(true)
for j = 3, 5 do
    local other_player = Player(players[j])
     party:addInvite(other_player)
    party:addMember(other_player)
end
 
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Dyabl0 said:
Is it possible to activate Shared Exp by LUA script when there is no option available for client? If so, does anyone have it?
Click to expand...
It's possible.
I don't have it.
What you need to do is pass unique exp value trough the addExperience() to activate custom exp part.

So lets say the maximum exp you can get at once is 20000.
This means whenever you add 20001 exp. You know its custom.
and it automatically uses different formula player:addExperince(exp-20000)
we need this because we don't want stackoverflow.


Only thing you need to do now is divide the exp in Player;onGainExperience(source, exp, rawExp) trough teammembers and give them divedExp+20000
now the same script executes again. but now it gets over 20000 exp and it will know that this exp came from party share. So it no longer divides it.

I prolly was too complicated and most likely there are better solutions. But this is how I would do that xD
 
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