Solved Dice Achiement Help.

[Mikii]

How would I know if the value (6) three times on dice ?
I don't find the logic for this on lua script.

No is possible?

EDIT

I just found the logic of how I can do this.
Just check the itemEx equals 5797. If true, then add 1 more to a storage until you get to three, otherwise add 0, and all back to start again.

SOLUTION

local storage = 123456
function onUse(cid, item, fromPosition, itemEx, toPosition)
    local player = Player(cid)
    local dice = Item(item.uid)
    local dicePosition = dice:getPosition()
    local value = math.random(1, 6)

    local isInGhostMode = player:isInGhostMode()
    if isInGhostMode then
        dicePosition:sendMagicEffect(CONST_ME_CRAPS, player)
    else
        dicePosition:sendMagicEffect(CONST_ME_CRAPS)
    end
    if value == 6 then
       if player:getStorageValue(storage) == -1 then player:setStorageValue(storage ,  0)  end
            player:setStorageValue(storage ,  (player:getStorageValue(storage) + 1) )
    else
        if player:getStorageValue(storage) ~= 3 then
            player:setStorageValue(storage , 0)
        end
    end
   
    player:say(player:getName() .. " rolled a " .. value .. ".", TALKTYPE_ORANGE_1, isInGhostMode, 0, dicePosition)
    dice:transform(5791 + value)
    return true
end

Close ths thread.

Sorry my Inlgish.