TFS 1.X+ Easiest check of items in a 3x3

[Mjmackan]

Alo! I'm looking for the best/shortest way to check for a certain item in a 3x3 shown as below:


My original idea was to write out every position and then do a for-loop with an if statement inside, something like:

local purplePos = {
{x,y,z}, {x,y,z}, {x,y,z},
{x,y,z}, {x,y,z}, {x,y,z},
{x,y,z}, {x,y,z}, {x,y,z},
}
for i = 1,9 do
 if getTileThingByPos(purplePos[i]).itemid ~= 9564 then
     return false
 end
end

(My first thought however is that the positions could be fetched in a better way, but not sure how.)

 

[Marko999x]

so u only want to check if from pos to pos has the current item inside?
or what exactly u mean?

 

[Night Wolf]

explain what need and not what you're trying to do, it will make it easier for someone to give you the optimal solution.

If you want to check if there's 3 similar colors in a line/column the solution is one, if you just want to iterate the 3x3 square I'd say you can just pass the corner position and do 2 loops:

local initialPos = {x = 100, y = 50, z = 7}
for i = 0, 2 do
    for j = 0, 2 do
        local tempPos = {x = initialPos.x + i, y = initialPos.y + j, z = initialPos.z}  
       --- Pick the item from temp position and make your check here
   end
end

 

[Mjmackan]

so u only want to check if from pos to pos has the current item inside?
or what exactly u mean?

Thats exactly what I want, excuse my poor explaining.

explain what need and not what you're trying to do, it will make it easier for someone to give you the optimal solution.

If you want to check if there's 3 similar colors in a line/column the solution is one, if you just want to iterate the 3x3 square I'd say you can just pass the corner position and do 2 loops:

local initialPos = {x = 100, y = 50, z = 7}
for i = 0, 2 do
    for j = 0, 2 do
        local tempPos = {x = initialPos.x + i, y = initialPos.y + j, z = initialPos.z}
       --- Pick the item from temp position and make your check here
   end
end

I want to check if there's a certain item on all tiles inside the 3x3 with as little code as possible, so your double loop is an awesome optimization.