NPC whos able to change DEC value to BIN one

[Ist]

Hey fellows,
I have a homework from my college, I am in need of making a program in C++ or any different language that is changing the IP adress choosen by user (e.g. 192.168.0.1) to a BIN one so 192.168.0.1 = 11000000.10101000.00000000.00000001

I think I am able to do it in C++ but I want to take some fun from that, so I am thinking about making a NPC whos changin it on a player requestDD

Is there anyone who is able to make such a thing so he can help me with that?;d
w'd be awesome, the A mark guaranteed I suppose

 

[PhoOwned]

I found it on polish forum. Change dec to bin.

math.dtb = function(decint)
	local binStr = ""
	repeat
		local mod = decint%2
		binStr = binStr .. (mod ~= 0 and "1" or "0")
		decint = math.floor(decint/2)
	until decint == 0
return binStr:reverse()
end

function changeIPtoBIN(ip_str)
 local ip = string.explode(ip_str, '.')
 for i= 1, #ip do
  ip[i] = math.dtb(ip[i])
 end
 return table.concat(ip, '.')
end

EDIT:
rest of polish post [translated]:

math.dth(decNumber) -- convert dec to hex (parameter is number, return string)
tonumber(hexString) -- default LUA function, convert hex to dec
math.dtb(decNumber) -- convert dec to bin (parameter is number, return string)
math.btd(binString) -- convert bin to dec (parameter is string, return number)

math.dth = function(decint)
	local hex, strHex = "0123456789ABCDEF", ""
	repeat
		local mod = decint%16+1
		strHex = strHex .. hex:sub(mod, mod)
		decint = math.floor(decint/16)
	until decint == 0
return "0x" .. strHex:reverse()
end
math.dtb = function(decint)
	local binStr = ""
	repeat
		local mod = decint%2
		binStr = binStr .. (mod ~= 0 and "1" or "0")
		decint = math.floor(decint/2)
	until decint == 0
return binStr:reverse()
end
math.btd = function(binstr)
	local out = 0
	binstr = binstr:reverse()
	for i=binstr:len(), 1, -1 do
		out = out + (tonumber(binstr:sub(i,i))*(2^(i-1)))
	end
return out
end

NOT TESTED

 

[Cykotitan]

cool, here's my decimal to binary lua function:

function Dec2Bin(v)
	local n, ret = tonumber(v), ''
	if not n or n < 0 then
		return
	end

	while n > 0 do
		ret = n % 2 .. ret
		n = math.floor(n / 2)
	end

	if ret:len() <3 then
		ret = ('0'):rep(3 - ret:len()) .. ret
	end
	return ret
end

 

[Ist]

Thanks I finally tried and I get used of it, added a few things like you're getting error if you're entering less/more of 8 numbers or if you are enterning characters