Lua Problem with tabble

[Critico]

I need to return the total table

tabble = {
["minotaur"] = {exp = 1000},
["globin"] = {exp = 2000},
["rotworm"] = {exp = 4000}
}

total: 3 ^

but if use '#tabble' returns 0


one way is as follows:

tabble = {
["minotaur"] = {exp = 1000},
["globin"] = {exp = 2000},
["rotworm"] = {exp = 4000}
}

local x = {}
for var, ret in pairs(tabble) do
table.insert(x, var)
end

print(#x) -- return 3

does anyone know another way?

 

[WarOfTheTitans]

Hmm, this:

tabble = {
["minotaur"] = {exp = 1000},
["globin"] = {exp = 2000},
["rotworm"] = {exp = 4000}
}
for k,v ipairs(tabble) do
...

btw... your last example was the way to solve it.

 

[Critico]

but has no other way instead of using ipairs?

 

[Shinmaru]

but has no other way instead of using ipairs?

tabble = {
["minotaur"] = {exp = 1000},
["globin"] = {exp = 2000},
["rotworm"] = {exp = 4000}
}
 
local x = {}
for i=0, #tabble - 1 do
  table.insert(x, tabble[i]) -- I suspect something is wrong here in this line. if it is returning 0
  print(i) -- Test Line to see if #tabble is being read properly
end
 
print(#x) -- return 3

 

[Critico]

not work

 

[dereker]

I dont understand what are you trying to do?

What's your goal, why are you lookinf for others way?

 

[Eskylo]

#table only counts when the index it's a positive number and I think there isn't a pre-made function in lua to count string indexes.

tabble = {
["minotaur"] = {exp = 1000},
["globin"] = {exp = 2000},
["rotworm"] = {exp = 4000}
}

i = 0
for _, _ in pairs(tabble) do
	i = i + 1
end

print(i) -- 3