Re-Learning C++

[Codex NG]

Since I have some extra time on my hands and would love to learn how to edit the sources I am reading & trying the examples on this site, (my c++ is terrible).
http://www.tutorialspoint.com/cplusplus/

So i am messing around with basic stuff like pointers and addresses, trying to increment them & their values.
Besides isn't this what programming is all about?

Trial and error..

Not exactly what I wanted

#include <iostream>
using namespace std;

int main()
{
    // integer array a with 3 elements
   int a[3] = {2, 2, 3};
   // integer pointer b which is pointing to a's address
   int *b = &a[0];
   // same thing as saying a[0] = a[0] + 1 
   *b = *b + 1;
   // shows the results
   cout << *b;
}

Still not what I wanted

#include <iostream>
using namespace std;

int main()
{
   int a[3] = {1, 2, 5};
   int *b = &a[0];
   // same as above but instead we use the size of *b which is 4 bytes
   for(int i = 0; i < (sizeof(*b) - 1); i++){
        // increment the pointer to point to a different address of a
       cout << *b++ <<endl;
   }
   
}

Almost there...

#include <iostream>
using namespace std;

int main()
{

   int a[3] = {1, 2, 5};
   int *b = &a[0];
   // this won't work as expected, it skips the initial index, post or pre it is always off by 1
   while(*++b){

       cout << *b <<endl;
   }
   
}

Ahhh, now we are getting somewhere

#include <iostream>
using namespace std;

int main()
{
   int a[3] = {1, 2, 5};
   int *b = &a[0];
   // this is what i wanted to do :D
   do{
       cout << *b <<endl;
   }while(*++b);
   
}

 

[president vankk]

C++ is a bitch.

 

[ZooTeam]

a and &a[0] are the "same"!!
Remember how pointers and arrays are associated.