Codex NG
Recurrent Flamer
- Joined
- Jul 24, 2015
- Messages
- 2,994
- Solutions
- 12
- Reaction score
- 1,657
Since I have some extra time on my hands and would love to learn how to edit the sources I am reading & trying the examples on this site, (my c++ is terrible).
http://www.tutorialspoint.com/cplusplus/
So i am messing around with basic stuff like pointers and addresses, trying to increment them & their values.
Besides isn't this what programming is all about?
Trial and error..
Not exactly what I wanted
Still not what I wanted
Almost there...
Ahhh, now we are getting somewhere
http://www.tutorialspoint.com/cplusplus/
So i am messing around with basic stuff like pointers and addresses, trying to increment them & their values.
Besides isn't this what programming is all about?
Trial and error..
Not exactly what I wanted
Code:
#include <iostream>
using namespace std;
int main()
{
// integer array a with 3 elements
int a[3] = {2, 2, 3};
// integer pointer b which is pointing to a's address
int *b = &a[0];
// same thing as saying a[0] = a[0] + 1
*b = *b + 1;
// shows the results
cout << *b;
}
Still not what I wanted
Code:
#include <iostream>
using namespace std;
int main()
{
int a[3] = {1, 2, 5};
int *b = &a[0];
// same as above but instead we use the size of *b which is 4 bytes
for(int i = 0; i < (sizeof(*b) - 1); i++){
// increment the pointer to point to a different address of a
cout << *b++ <<endl;
}
}
Almost there...
Code:
#include <iostream>
using namespace std;
int main()
{
int a[3] = {1, 2, 5};
int *b = &a[0];
// this won't work as expected, it skips the initial index, post or pre it is always off by 1
while(*++b){
cout << *b <<endl;
}
}
Ahhh, now we are getting somewhere
Code:
#include <iostream>
using namespace std;
int main()
{
int a[3] = {1, 2, 5};
int *b = &a[0];
// this is what i wanted to do :D
do{
cout << *b <<endl;
}while(*++b);
}