Runes based on count, not charges [8.54]

[Erexo]

Hello there,
Ive put a normal, useable, stackable item into rune script.
Main idea is to create an mwall "rune" but in normal stackable item, and when you cast that "rune", 1 count from stack will be loss, not whole stack (runes based on item count, not charges).
Ive found out that:

bool RuneSpell::executeUse(Player* player, Item* item, const PositionEx& posFrom,
    const PositionEx& posTo, bool extendedUse, uint32_t creatureId)
{
    if(!playerRuneSpellCheck(player, posTo))
        return false;

    bool result = false;
    if(isScripted())
    {
        LuaVariant var;
        if(creatureId && needTarget)
        {
            var.type = VARIANT_NUMBER;
            var.number = creatureId;
        }
        else
        {
            var.type = VARIANT_POSITION;
            var.pos = posTo;
        }

        result = internalCastSpell(player, var);
    }
    else if(function)
        result = function(this, player, item, posFrom, posTo);

    if(result)
    {
        Spell::postCastSpell(player);
        if(hasCharges && item && g_config.getBool(ConfigManager::REMOVE_RUNE_CHARGES))
            g_game.transformItem(item, item->getID(), std::max((int32_t)0, ((int32_t)item->getCharges()) - 1));
    }

    return result;
}

there is that line:

g_game.transformItem(item, item->getID(), std::max((int32_t)0, ((int32_t)item->getCharges()) - 1));

But I dont really know how to change it that it will remove count, not charge.
Any ideas? Im using tfs0.3.6pl1

Greetings,
Erexo

 

[Erexo]

Fixed, found method for item count.
If someone needs:

g_game.transformItem(item, item->getID(), std::max((int32_t)0, ((int32_t)item->getItemCount()) - 1));