Script lua tfs 1.2

[gubbo123]

How can i do a script like this

Uaing function onUse,

I have a item sequence id 2000 to 2050
When i use this item 2000 will transform to id 2001, when i use this 2001 item transform to 2002, after when i use the last item of sequence 2050, back to first item again 2000

 

[Addams]

I am not sure if I missed any ids but I think this should work.

local decayItems = {
    [2000] = 2001, [2001] = 2002, [2002] = 2003, [2003] = 2004, [2004] = 2005, [2006] = 2007, [2007] = 2008, [2008] = 2009, [2009] = 2010,
    [2010] = 2011, [2011] = 2012, [2012] = 2013, [2013] = 2014, [2014] = 2015, [2015] = 2016, [2016] = 2017, [2017] = 2018,
    [2018] = 2019, [2019] = 2020, [2020] = 2021, [2021] = 2022, [2022] = 2023, [2023] = 2024, [2024] = 2025, [2025] = 2026,
    [2026] = 2027, [2027] = 2028, [2028] = 2029, [2029] = 2030, [2030] = 2031, [2031] = 2032, [2032] = 2033, [2033] = 2034,
    [2034] = 2035, [2035] = 2036, [2036] = 2037, [2037] = 2038, [2038] = 2039, [2039] = 2040, [2040] = 2041, [2041] = 2042,
    [2042] = 2043, [2043] = 2044, [2044] = 2045, [2045] = 2046, [2046] = 2047, [2047] = 2048, [2048] = 2049, [2049] = 2050, [2050] = 2000
}

function onUse(player, item, fromPosition, target, toPosition, isHotkey)
    local decayItemId = decayItems[item:getId()]
    if not decayItemId then
        return false
    end

    item:transform(decayItemId)
    item:decay()
    return true
end

 

[Infernum]

There's no need for a table:

function onUse(player, item, fromPosition, target, toPosition, isHotkey)
    local newId = item:getId() + 1
    if newId > 2050 then
        newId = 2000
    end
    item:transform(newId)
    return true
end

<action fromid="2000" toid="2050" script="xxx.lua" />