Script that checks items and it counts.

[Swiftxd]

Hey, i have a question, if i uses a item in a item2, how can i made it gives more than 1 item, like, check every item and its counts. Heres an Example:

config = {
[item] = {loot={{1145, 5},{8181, 1},{1273, 8}}, level=5, xp=5}
}

i need check how much itens have on loot and then uses doPlayerAddItem(cid, loot[1], loot[2]) get it ?
but i dont want to make 100 ifs, or make 3 doPlayerAddItem function, how can i do that ?

 

[Mkalo]

Try again, cant understand you.

Maybe this?

local items = config[item.itemid].loot
for i = 1, #items do
    doPlayerAddItem(cid, items[i][1], items[i][2])
end

 

[Swiftxd]

Try again, cant understand you.

Maybe this?

local items = config[item.itemid].loot
for i = 1, #items do
    doPlayerAddItem(cid, items[i][1], items[i][2])
end

Thx dude, but i found it by myself, is quite simple, i used "for i,v ipairs"

 

[Codex NG]

Thx dude, but i found it by myself, is quite simple, i used "for i,v ipairs"

share the solution.. so we can understand your original question.

 

[Yamaken]

Try again, cant understand you.

Maybe this?

local items = config[item.itemid].loot
for i = 1, #items do
    doPlayerAddItem(cid, items[i][1], items[i][2])
end

Why you are not using ipairs?

 

[Mkalo]

Why you are not using ipairs?

Because I always did it like this and it's slightly faster (not really much you shouldn't bother).

 

[whitevo]

In the Opening post example we cant use ipairs() because ipairs starts from 1..2..3..4..5 etc.
if you use itemID as the key then it quite frankly cant start from 1 and more over have a secuence.

for i=1, #table do
also is bad solution, its almost same as ipairs

the only option here is: for k, v in pairs() do If we use the configuration file given by opening post.

And as much as I understood, he wants double loop trough. trough config and loot table.

 

[Mkalo]

In the Opening post example we cant use ipairs() because ipairs starts from 1..2..3..4..5 etc.
if you use itemID as the key then it quite frankly cant start from 1 and more over have a secuence.

for i=1, #table do
also is bad solution, its almost same as ipairs

the only option here is: for k, v in pairs() do If we use the configuration file given by opening post.

And as much as I understood, he wants double loop trough. trough config and loot table.

You don't have to loop through the config table if he already has the "key" that he is looking for that is an itemid.

You just have to do:
local items = config[item.itemid].loot
Ofc you should check before if config[item.itemid] exists depending on what you are doing.

And this table starts from 1..2..3..4..5 etc.

 

[whitevo]

ok nvm, misunderstood post 1.

 

[Swiftxd]

Sorry guys, I have been busy in the last days, and sorry for bad grammar.
here's the code:

local reward = config[item].loot
        for i, v in ipairs(reward) do
                doPlayerAddItem(cid, reward[i][1], math.random(0,reward[i][2]+(getEnchantingSkill(cid)*0.03)) or 1)
        end

the question was how i can add more than one item in a single function, but i found it by myself, yamaken was right. Thanks.