Lua Tables

[GarQet]

Hello OTlanders. I got small request. I don't how to create one additional to my script.
I got this:

	local a = {0, 10, 55}
	local b = {"GarQet", "Otland", "Script"}
	local l = 0

And now:

for v = 1, 3 do
	if getCreatureName(cid) == b[v] then
		l = a[v]
	end
end
doPlayerAddLevel(cid, l)

I want this: If player is named GarQet then script took information from table a assigned to the number of which was the name of the table b.
So, If GarQet (from table B) then 0 (from table A).
If creature is named Script (from table B) then 55 (from table A).

Someone understand my request and can help me in this?

 

[TGYoshi]

I'd say, do it like this (I'd prefer to wipe it even further, but I'll keep it a bit like how you want it to be..):

local a = {0, 10, 55}
local b = {"GarQet", "Otland", "Script"}
...
local n = getCreatureName(cid)
for i,v in pairs(b) do
if v==n then
doPlayerAddLevel(cid, a[i])
break
end
end

Your (old..) script got a nice exploit in it as well, since when nothing matches the previous 'l' value will be used.

 

[Lightonia]

GarQet send me a PM ure inbox is full im interested in some of ure events

 

[sn3ejk]

local config, player = {["GarQet"] = 0, ["Otland"] = 10, ["Script"] = 55}, getCreatureName(cid)
	for name, level in pairs(config) do
		if (player == name) then
			doPlayerAddLevel(cid, level)
		end
	end