Multiple items in table

[Ratser]

How can I use more than 1 itemid in a table?

I tried with this...and failed:

function onUse(cid, item, fromPosition, itemEx, toPosition)
	local ITEMS =
	{
		[{8977, 9002}] = {"PUDDI PUDDI PUDDI PUDDI"}
	}

	local items = ITEMS[{item.itemid}]
	if(not items) then
		return false
	end
	
	doCreatureSay(cid, items[2], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))

	return true
end

 

[Santi]

Uhm, what about if you use a for?
for k, v in pairs
And use k[1] and k[2] for the items?

 

[Ratser]

Ok, I tried with this:

function onUse(cid, item, fromPosition, itemEx, toPosition)
	local ITEMS =
	{
		[{8977, 9002}] = {"DESU DESU", "PUDDI PUDDI"},
		[{8981, 9004}] = {"MUD", "KIP"}
	}
	
	for k, v in pairs(ITEMS) do
		doCreatureSay(cid, v[2], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))
	end

	return true
end

But 'v[2]' is making all of the items above say the second sound of each item in the table. (e.g. When I use itemid = 8977 it says "PUDDI PUDDI" and "KIP" at the same time)

 

[Santi]

But you are not checking the k, example:

function onUse(cid, item, fromPosition, itemEx, toPosition)
	local ITEMS =
	{
		[{8977, 9002}] = {"DESU DESU", "PUDDI PUDDI"},
		[{8981, 9004}] = {"MUD", "KIP"}
	}
 
	for k, v in pairs(ITEMS) do
            if item.itemid == k[1] then
		doCreatureSay(cid, v[2], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))
	end
 
	return true
end

 

[Ratser]

Ok, I got it.

BTW, in this one...

function onUse(cid, item, fromPosition, itemEx, toPosition)
	local DIRECT =
	{
		[{8977, 9002}] = {"DESU DESU", "PUDDI PUDDI"},
		[{8981, 9004}] = {"MUD", "KIP"}
	}
	
	for k, v in pairs(DIRECT) do
		if item.itemid == k[1] or item.itemid == k[2] then
			doCreatureSay(cid, v[2], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))
		end
	end

	return true
end

...is there any way to shorten this:

if item.itemid == k[1] or item.itemid == k[2] then

EDIT:
Doesn't matter anymore...I made it with

if(isInArray(k, item.itemid)) then

kthxbai

 

[Santi]

Uhm I think that using isInArray shud work

if isInArray({k[1],k[2]},item.itemid) then

But remember, that if you put at doCreatureSay only v[2]
Then if use either first or second item, it will say PUDDI PUDDI and it'll never say DESU DESU

 

[Ratser]

Yeh, I know I edited my last post. I'll put math.random later. Thx

 

[Santi]

Yeh, I know I edited my last post. I'll put math.random later. Thx

No worries

 

[knightxd]

Ok, I got it.

BTW, in this one...

function onUse(cid, item, fromPosition, itemEx, toPosition)
	local DIRECT =
	{
		[{8977, 9002}] = {"DESU DESU", "PUDDI PUDDI"},
		[{8981, 9004}] = {"MUD", "KIP"}
	}
	
	for k, v in pairs(DIRECT) do
		if item.itemid == k[1] or item.itemid == k[2] then
			doCreatureSay(cid, v[2], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))
		end
	end

	return true
end

...is there any way to shorten this:

if item.itemid == k[1] or item.itemid == k[2] then

EDIT:
Doesn't matter anymore...I made it with

if(isInArray(k, item.itemid)) then

kthxbai

n = max
for i = k[1], k[n] do
for k, v in pairs(DIRECT) do
		if isInArray({k[i]},item.itemid) then
doCreatureSay(cid, v[i], TALKTYPE_MONSTER, false, 0, fromPosition.x ~= CONTAINER_POSITION and fromPosition or getThingPos(cid))

try som like that, sorry, i got no time today.. :X

 

[chojrak]

Best have an epic fail with arrays. Why so puddi tho?

 

[devianceone]

no need to use tables like that lol
lua-users wiki: Tables Tutorial

 

[Ratser]

best have an epic fail with arrays. Why so puddi tho?

NO U don't mess with puddi

no need to use tables like that lol
lua-users wiki: Tables Tutorial

Exactly which one would fit here?

 

[devianceone]

it looks like you're trying to have 4 items give 4 different messages, so why use a table w/ 2 items as a key? why not just a normal 1 key and 1 value table?

 

[Ratser]

No. I was trying to have pairs of 2 different items give similar messages.

 

[devianceone]

[{8977, 9002}] = {"DESU DESU", "PUDDI PUDDI"},
[{8981, 9004}] = {"MUD", "KIP"}

??? whats the point of 4 messages then

 

[Ratser]

2 messages for each pair of items.

e.g.
If the itemid is 8977 or 9002 then the message will be "DESU DESU" or "PUDDI PUDDI".
If the itemid is 8981 or 9004 then the message will be "MUD" or "KIP".

 

[PhoOwned]

items = {[8977] = {"DESU DESU", "PUDDI PUDDI"}, [9002] = items[8977],
[8981] = {"MUD", "KIP"}, [9004] = items[8981]}

for i=1,#items do
print(items[i][math.random(1,#items[i])])
end

Not tested

 

[Santi]

This is kinda solved, no need to keep posting.

 

[Ratser]

>>1113328
Solved...damn stalkers.