Solved How does the monster's drop rate work?

[Lizard Helper]

First, I apologize if it's the wrong place to ask. I've been looking around but find no answer.

I'm trying to adjust the drop rate of creatures' loot so that it's similar to Tibia's. The problem is I don't know how to do that. If I want monster to drop an item say 10% of the time, or 100%, or 50%. If anyone could either give a quick explanation or point me to an already existing tutorial or similar, I'd be very grateful.

 

[tansolounamirad]

noobie

 

[Lizard Helper]

Thank you; your reply was very helpful. You must be quite an asset to this community.

 

[chojrak]

From source code:

uint16_t Monsters::getLootRandom()
{
	return (uint16_t)std::ceil((double)random_range(0, MAX_LOOTCHANCE) / g_config.getDouble(ConfigManager::RATE_LOOT));
}

&

Item* MonsterType::createLoot(const LootBlock& lootBlock)
{
	uint16_t item = lootBlock.ids[0], random = Monsters::getLootRandom();
	if(lootBlock.ids.size() > 1)
		item = lootBlock.ids[random_range((size_t)0, lootBlock.ids.size() - 1)];

	Item* tmpItem = NULL;
	if(Item::items[item].stackable)
	{
		if(random < lootBlock.chance)
			tmpItem = Item::CreateItem(item, (random % lootBlock.count + 1));
	}
	else if(random < lootBlock.chance)
		tmpItem = Item::CreateItem(item, 0);

	if(!tmpItem)
		return NULL;

	if(lootBlock.subType != -1)
		tmpItem->setSubType(lootBlock.subType);

	if(lootBlock.actionId != -1)
		tmpItem->setActionId(lootBlock.actionId, false);

	if(lootBlock.uniqueId != -1)
		tmpItem->setUniqueId(lootBlock.uniqueId);

	if(!lootBlock.text.empty())
		tmpItem->setText(lootBlock.text);

	return tmpItem;
}

&

MAX_LOOTCHANCE is 100000

 

[Lizard Helper]

Thanks a bunch! =)

 

[Sentielo]

It's the same with seconds =), one second is 1000, one percent is 1000.
Here a short list for you:
100% = 100000
10% = 10000
1% = 1000
0.1% = 100
0.01% = 10